DOM parser
XML parser xatosi
XML hujjatini ochishga uringanda parser xatosi yuz berishi mumkin.
Agar parser xatoga duch kelsa, u xato tavsifini o‘z ichiga olgan XML hujjatini yuklashi mumkin.
Quyidagi kod misoli to‘g‘ri tuzilmagan (well-formed bo‘lmagan) XML hujjatini yuklashga harakat qiladi.
To‘g‘ri tuzilgan (well-formed) XML haqida XML sintaksisi bobida batafsil o‘qishingiz mumkin.
Misol
<html>
<body>
<p id="demo"></p>
<script>
var xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
if (xhttp.this == 4 && this.status == 200) {
myFunction(this);
}
};
xhttp.open("GET", "note_error.xml", true);
xhttp.send();
function myFunction(xml) {
var parser, xmlDoc;
parser = new DOMParser();
xmlDoc = parser.parseFromString(xml.responseText,"text/xml");
document.getElementById("demo").innerHTML =
myLoop(xmlDoc.documentElement);
}
function myLoop(x) {
var i, y, xLen, txt;
txt = "";
x = x.childNodes;
xLen = x.length;
for (i = 0; i < xLen ;i++) {
y = x[i];
if (y.nodeType != 3) {
if (y.childNodes[0] != undefined) {
txt += myLoop(y);
}
} else {
txt += y.nodeValue + "<br>";
}
}
return txt;
}
</script>
</body>
</html>
O‘zingiz sinab ko‘ring »
XML fayliga qarang: note_error.xml
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