DateDiff
Misol
Ikki sana orasidagi farqni yillarda qaytarish:
SELECT DateDiff("yyyy", #13/01/1998#, #09/05/2017#);
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Ta’rif va qo‘llanilishi
DateDiff() funksiyasi ikki sana orasidagi farqni qaytaradi.
Sintaksis
DateDiff(datepart, date1, date2, firstdayofweek, firstweekofyear)
Parametr qiymatlari
| Parametr | Tavsif |
|---|---|
| datepart | Required. The part to return. Can be one of the following values:
|
| date1 va date2 | Majburiy. O‘rtasidagi farqni hisoblash uchun ikki sana |
| firstdayofweek | Optional. Specifies the first day of the week.
Can be one of the following values:
|
| firstdayofyear | Optional. Specifies the first week of the year. Can be one of the following values:
|
Texnik tafsilotlar
| Qo‘llab-quvvatlaydigan tizimlar: | MS Access 2000 versiyasidan boshlab |
|---|
Ko‘proq misollar
Misol
Ikki sana orasidagi farqni oylarda qaytarish:
SELECT DateDiff("m", #13/01/1998#, #09/05/2017#);
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Misol
Belgilangan sana va bugungi kun o‘rtasidagi farqni kunlarda qaytaring:
SELECT DateDiff("d", #13/01/1998#, Date());
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